Page 23 - eEC20510_化工裝置(上)_課本PDF

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化工裝置

例題 1-1

༊Ӌᓂܓٙ 1p€poise= kg/mgs= p gsf
a
解 1 g 1 kg 100 cm
μ=1p= × × =0.1 kg/mgs
cmgs 1000g 1 m
kg 1 Ngs 2 Ngs
μ=0.1 × =0.1 2 =0.1 p gs
mgs 1 kggm m a

例題 1-2

g kg lb
༊Ӌ੗ܓ 1( )= ( 3 )= ( m ) k
cm 3 m ft 3

解 g g 1 kg 100 cm g 1 kg 100 cm 3
3
3
1( )=1 3 × ×( ) =1 × ×
cm 3 cm 1000 g 1 m cm 3 1000 g 1 m 3
= 10 6 ( kg )=1000( kg )
1000 m 3 m 3
g g 1 lb 30.48 cm
1( )=1 × m ×( ) 3
cm 3 cm 3 453.6 g 1 ft
g 1 lb 30.48 cm 3
3
=1 × m ×
cm 3 453.6 g 1 ft 3
30.48 3 lb lb
= ( m )=62.4 m 。
453.6 ft 3 ft 3

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ʷʈༀໄ ɪ DI JOEE ɪʹ