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第 10 章
                                                                                                                   熱化學




                       範例 10-3

                      試求出 C + 2H      2(g)    CH 4(g)  在 25℃之反應熱為若干 kcal ?
                               (s)
                      已知 C + O    2(g)    CO         ΔH =- 94.05 kcal
                            (s)
                                           2(g)
                                  1
                         H   2(g)  +  O 2(g)    H O           ΔH =- 68.32 kcal
                                               (l)
                                            2
                                  2
                         CH   4(g)  + 2O 2(g)    CO 2(g)  + 2H O       ΔH =- 212.80 kcal
                                                        (l)

                                                      2
                       解
                                 C + O  2(g)    CO 2(g)             ΔH =- 94.05 kcal
                                  (s)
                                 2H 2(g)  + O 2(g)    2H O (l)      ΔH =- 68.32×2 kcal
                                                  2
                           + ) CO   2(g)  + 2H O (1)    CH 4(g)  + 2O 2(g)  ΔH = 212.80 kcal
                                            2
                                 C + 2H  2(g)    CH 4(g)            ΔH =- 17.89 kcal
                                  (S)




                       範例 10-4
                                      1      3
                      已知 NH   3(g)    N 2(g)  +  H   ΔH = 11.0 kcal
                                                 2(g)
                                    2        2
                           1
                             N 2(g)  + O 2(g)   NO 2(g)        ΔH = 8.1 kcal
                           2
                                 1
                        H   2(g)  +  O 2(g)   H O      ΔH =- 57.8 kcal
                                            2
                                              (g)
                                 2
                                 7                 3
                      求 NH    +    O      NO    +    H O 之反應熱為若干?
                            3(g)
                                 4   2(g)    2(g)   2  2  (g)

                       解
                                          1        3
                                 NH         N   +    H                ΔH = 11.0 kcal
                                    3(g)
                                          2   2(g)  2  2(g)
                                 1
                                 2  N 2(g)  + O 2(g)    NO 2(g)       ΔH = 8.1 kcal
                                 3         3        3                                 3
                           + )   2  H 2(g)  +  4  O 2(g)      2  H O (g)  ΔH =- 57.8×  2   =- 86.7kcal
                                                        2
                                         7                 3
                                 NH    +    O      NO   +    H O      ΔH =- 67.6 kcal
                                    3(g)
                                         4   2(g)     2(g)  2  2  (g)











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          ౷ஷʷኪ ɨ DI   JOEE                                                                                                    ɨʹ
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